From PyPI:
pip install timeoutd
From source code:
git clone https://github.com/juhannc/timeoutd.git
pip install -e .
The timeoutd
module provides a decorator that can be used to limit the execution time of a function.
The decorator takes a single argument, the number of seconds or a specific date (as a datetime object) after which the function should be terminated.
import time
import timeoutd
@timeoutd.timeout(5)
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
The timeout
decorator allows for multiple different ways to specify the timeout, for example with a datetime object:
import time
import datetime
import timeoutd
@timeoutd.timeout(datetime.datetime.now() + datetime.timedelta(0, 5))
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
It also take a timedelta
object:
import time
import datetime
import timeoutd
@timeoutd.timeout(datetime.timedelta(0, 5))
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
But it can also take a delta in form of hours, minutes, and seconds via the kwargs:
import time
import timeoutd
@timeoutd.timeout(hours=0, minutes=0, seconds=5)
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
The timeout
decorator also accepts a custom exception to raise on timeout:
import time
import timeoutd
@timeoutd.timeout(5, exception_type=StopIteration)
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
You can also specify a function to be called on timeout instead of raising an exception:
import time
import timeoutd
def add_two_numbers(i: int, j: int | None = None):
if j is None:
j = 0
print(f"The sum of {i = } and {j = } is {i + j}")
@timeoutd.timeout(
5,
on_timeout=add_two_numbers,
on_timeout_args=(1,),
on_timeout_kwargs={"j": 2}
)
def mytest():
print("Start")
for i in range(1, 10):
time.sleep(1)
print(f"{i} seconds have passed")
if __name__ == '__main__':
mytest()
Note: This feature appears to be broken in some cases for the original timeout-decorator. Some issues might still exist in this fork.
By default, timeoutd
uses signals to limit the execution time of the given function.
This approach does not work if your function is executed not in a main thread (for example if it's a worker thread of the web application).
There is alternative timeout strategy for this case - by using multiprocessing.
To use it, just pass use_signals=False
to the timeout decorator function:
import time
import timeoutd
@timeoutd.timeout(5, use_signals=False)
def mytest():
print "Start"
for i in range(1, 10):
time.sleep(1)
print("{} seconds have passed".format(i))
if __name__ == '__main__':
mytest()
Warning: Make sure that in case of multiprocessing strategy for timeout, your function does not return objects which cannot be pickled, otherwise it will fail at marshalling it between master and child processes.
Derived from http://www.saltycrane.com/blog/2010/04/using-python-timeout-decorator-uploading-s3/, https://code.google.com/p/verse-quiz/source/browse/trunk/timeout.py, and https://github.com/pnpnpn/timeout-decorator