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Minimize the Maximum Adjacent Element Difference
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Goutham Vidya Pradhan
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Goutham Vidya Pradhan
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Dec 5, 2024
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107 changes: 107 additions & 0 deletions
107
src/main/java/binary_search/MinimizeTheMaximumAdjacentElementDifference.java
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package binary_search; | ||
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import java.util.ArrayList; | ||
import java.util.Arrays; | ||
import java.util.List; | ||
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public class MinimizeTheMaximumAdjacentElementDifference { | ||
record Interval(int s, int e, boolean hasMoreThanOne){ | ||
static boolean check(int a, int mid, int b, int range){ | ||
return Math.abs(mid - a) <= range && Math.abs(mid - b) <= range; | ||
} | ||
static boolean check(int a, int mid1, int mid2, int b, int range){ | ||
return Math.abs(mid1 - a) <= range && Math.abs(mid1 - mid2) <= range && Math.abs(mid2 - b) <= range; | ||
} | ||
} | ||
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public static void main(String[] args) { | ||
int[] nums = new int[]{-1,10,-1,8}; | ||
int res = new MinimizeTheMaximumAdjacentElementDifference().minDifference(nums); | ||
System.out.println(res); | ||
} | ||
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public int minDifference(int[] nums) { | ||
boolean noPositiveNum = Arrays.stream(nums).filter(i -> i != -1).findAny().isEmpty(); | ||
if(noPositiveNum){ | ||
return 0; | ||
} | ||
int currentMax = getCurrentMax(nums); | ||
List<Interval> intervals = buildIntervals(nums); | ||
int minStart = Integer.MAX_VALUE, maxEnd = Integer.MIN_VALUE; | ||
for (Interval interval : intervals) { | ||
minStart = Math.min(minStart, Math.min(interval.e, interval.s)); | ||
maxEnd = Math.max(maxEnd, Math.max(interval.e, interval.s)); | ||
} | ||
int l = 0, h = maxEnd, m; | ||
int ans = -1; | ||
while(l <= h){ | ||
m = l + (h - l) / 2; | ||
boolean result = checkIfThisNumberSatisfiesAllIntervals(intervals, minStart + m, maxEnd - m, m); | ||
if(result){ | ||
ans = m; | ||
h = m - 1; | ||
} else { | ||
l = m + 1; | ||
} | ||
} | ||
return Math.max(ans, currentMax); | ||
} | ||
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private int getCurrentMax(int[] nums){ | ||
int currMax = Integer.MIN_VALUE; | ||
int previous = nums[0]; | ||
for(int i = 1; i < nums.length; i ++){ | ||
if(nums[i] != -1){ | ||
if(previous != -1){ | ||
currMax = Math.max(currMax, Math.abs(previous - nums[i])); | ||
} | ||
previous = nums[i]; | ||
} else { | ||
previous = -1; | ||
} | ||
} | ||
return currMax; | ||
} | ||
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private List<Interval> buildIntervals(int[] nums) { | ||
int previous = -1; | ||
int minusOneCount = 0; | ||
List<Interval> intervals = new ArrayList<>(); | ||
for (int num : nums) { | ||
if (num == -1) { | ||
minusOneCount ++; | ||
} else { | ||
if (minusOneCount > 0) { | ||
intervals.add(new Interval(previous != -1 ? previous : num, num, minusOneCount > 1)); | ||
minusOneCount = 0; | ||
} | ||
previous = num; | ||
} | ||
} | ||
if(nums[nums.length - 1] == -1){ | ||
intervals.add(new Interval(previous, previous, minusOneCount > 1)); | ||
} | ||
return intervals; | ||
} | ||
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boolean checkIfThisNumberSatisfiesAllIntervals(List<Interval> intervals, int minStart, int maxEnd, int maxDiff){ | ||
for (Interval interval : intervals) { | ||
if (interval.hasMoreThanOne) { | ||
boolean res1 = Interval.check(interval.s, minStart, minStart, interval.e, maxDiff); | ||
boolean res2 = Interval.check(interval.s, minStart, maxEnd, interval.e, maxDiff); | ||
boolean res3 = Interval.check(interval.s, maxEnd, minStart, interval.e, maxDiff); | ||
boolean res4 = Interval.check(interval.s, maxEnd, maxEnd, interval.e, maxDiff); | ||
if (!res1 && !res2 && !res3 && !res4) { | ||
return false; | ||
} | ||
} else { | ||
boolean res1 = Interval.check(interval.s, minStart, interval.e, maxDiff); | ||
boolean res2 = Interval.check(interval.s, maxEnd, interval.e, maxDiff); | ||
if (!res1 && !res2) { | ||
return false; | ||
} | ||
} | ||
} | ||
return true; | ||
} | ||
} |