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solutions/beecrowd/2994/2994.sql

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+SELECT doctor.name, ( ( 1 * 150 ) + 1 ) + ( ( 2 * 150 ) + 15 ) FROM attendances
+JOIN doctors ON doctors.id = attendances.id_doctor
+JOIN work_shifts ON work_shifts.id = attendances.id_work_shift
+GROUP BY attendances.id
+ORDER BY doctors.name;

solutions/beecrowd/2994/drop-table.sql

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+DROP TABLE attendances;
+DROP TABLE work_shifts;
+DROP TABLE doctors;

solutions/beecrowd/2994/problem.md

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+https://judge.beecrowd.com/en/problems/view/2994
+
+# How much does a Doctor earn?
+
+You work in the IT sector for a hospital and need to calculate the payment
+revenue from each of the doctors. Each doctor earns 150$ per hour plus a
+percentage that depends on the work shift. For example, the doctor Wellington
+worked 1 hour in the day shift, and 2 hours in the night shift, therefore his
+weekly salary will be: ( ( 1 * 150 ) + 1% ) + ( ( 2 * 150 ) + 15% ) = 496.5.
+Furthermore, you can use the function ROUND(value,1) to show the salary with 1
+decimal place e order the result from the highest to lowest salary.

solutions/beecrowd/2994/schema.sql

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+--- URI Online Judge SQL
+--- Copyright URI Online Judge
+--- www.urionlinejudge.com.br
+--- Problem 2994
+
+CREATE TABLE doctors (
+id integer PRIMARY KEY,
+name varchar(50)
+);
+
+GRANT SELECT ON doctors TO sql_user;
+
+CREATE TABLE work_shifts (
+id integer PRIMARY KEY,
+name varchar(50),
+bonus numeric
+);
+
+GRANT SELECT ON work_shifts TO sql_user;
+
+CREATE TABLE attendances (
+id integer PRIMARY KEY,
+id_doctor integer,
+hours integer,
+id_work_shift integer,
+FOREIGN KEY (id_doctor) REFERENCES  doctors(id),
+FOREIGN KEY (id_work_shift) REFERENCES  work_shifts(id)
+);
+
+GRANT SELECT ON attendances TO sql_user;
+
+insert into doctors (id,name) values
+(1,'Arlino'),
+(2,'Tiago'),
+(3,'Amanda'),
+(4,'Wellington');
+
+insert into work_shifts (id,name,bonus) values
+(1,'nocturnal',15),
+(2,'afternoon',2),
+(3,'day',1);
+
+insert into  attendances (id, id_doctor, hours, id_work_shift) values
+(1,1,5,1),
+(2,3,2,1),
+(3,3,3,2),
+(4,2,2,3),
+(5,1,5,3),
+(6,4,1,3),
+(7,4,2,1),
+(8,3,2,2),
+(9,2,4,2);
+
+/*  Execute this query to drop the tables */
+-- DROP TABLE attendances;
+-- DROP TABLE work_shifts;
+-- DROP TABLE doctors;

solutions/beecrowd/2994/tags.txt

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+sql