release: 2.4.1

CHANGELOG.md

@@ -1,6 +1,14 @@
 Release History
 ===============
 
+### Version 2.4.1
+
+Released on May 10, 2020
+
+- fix type hint for `stellar_sdk.Server.submit_transaction()`.
+- fix broken links in examples.
+
+
 ### Version 2.4.0
 
 Released on May 05, 2020

README.rst

@@ -57,7 +57,7 @@ Install and update using `pipenv`_ or `pip`_:
 
 .. code-block:: text
 
-    pip install stellar-sdk==2.4.0
+    pip install stellar-sdk==2.4.1
 
 
 A Simple Example

docs/en/install.rst

@@ -11,7 +11,7 @@ To install py-stellar-sdk, use pipenv to install the module:
 
 .. code-block:: text
 
-    pipenv install stellar-sdk==2.4.0
+    pipenv install stellar-sdk==2.4.1
 
 If you're not using `pipenv <https://docs.pipenv.org/>`_, you should.
 Otherwise, you can install it via plain old `pip <https://pip.pypa.io/en/stable/quickstart/>`_. More on installing Python
@@ -29,5 +29,5 @@ You can clone `the repository <https://github.com/StellarCN/py-stellar-base>`_ d
 
     git clone https://github.com/StellarCN/py-stellar-base.git
     cd py-stellar-base
-    git checkout 2.4.0
+    git checkout 2.4.1
     pip install .

docs/zh_CN/install.rst

@@ -11,7 +11,7 @@
 
 .. code-block:: text
 
-    pipenv install stellar-sdk==2.4.0
+    pipenv install stellar-sdk==2.4.1
 
 我们推荐你使用 `pipenv <https://docs.pipenv.org/>`_ 来安装这个模块。当然你也可以使用 `pip <https://pip.pypa.io/en/stable/quickstart/>`_。
 想要更多的了解如何安装依赖，请参阅 `Hitchhiker's Guide to Python
@@ -28,5 +28,5 @@
 
     git clone https://github.com/StellarCN/py-stellar-base.git
     cd py-stellar-base
-    git checkout 2.4.0
+    git checkout 2.4.1
     pip install .

stellar_sdk/__version__.py

@@ -11,7 +11,7 @@
 __description__ = "The Python Stellar SDK library provides APIs to build transactions and connect to Horizon."
 __url__ = "https://github.com/StellarCN/py-stellar-base"
 __issues__ = "{}/issues".format(__url__)
-__version__ = "2.4.0"
+__version__ = "2.4.1"
 __author__ = "Eno, overcat"
 __author_email__ = "[email protected], [email protected]"
 __license__ = "Apache License 2.0"