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Fixed util/parse_number for numbers with >2 digits #33

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@MaienM MaienM commented Nov 10, 2022

In these cases the digits at the start of the number would be multiplied by too many powers of ten, inflating the result (123 -> 1203, 1234 -> 1203004, etc).

In these cases the digits at the start of the number would be multiplied
by too many powers of ten, inflating the result (123 -> 1203, 1234 ->
1203004, etc).
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