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近期公司项目告一段落,闲来无事,看到山东中国移动客户端有个转盘动画挺酷的。于是试着实现一下,看似简单,可在coding时却发现不少坑,填坑的同时还顺便复习了一下高中数学知识([三角函数]),收获不小。


[Demo] & 效果图:

![转盘旋转效果图][效果图]


###1、首先初始化6个UIImageView

######1)分析imgView的中心点位置

![imgView的中心点位置][center.001.jpg]

𝜟x = _radius * sin(α); 𝜟y = _radius * cos(α); 所以, imgView.center.x = centerX + _radius * sin(currentAngle); imgView.center.y = centerY - _radius * cos(currentAngle);

######2)代码

``` - (void)customUI { CGFloat centerX = CGRectGetWidth(self.frame) * 0.5f; CGFloat centerY = centerX; _centerPoint = CGPointMake(centerX, centerY);//中心点 _blueView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 100, 100)];//蓝色view _blueView.center = _centerPoint; _blueView.backgroundColor = [UIColor blueColor]; [self addSubview:_blueView]; UIView *redView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 50, 50)];//红色view redView.backgroundColor = [UIColor redColor]; [_blueView addSubview:redView];
_deltaAngle = M_PI / 3.0f;//6个imgView的间隔角度
CGFloat currentAngle = 0;
CGFloat imgViewCenterX = 0;
CGFloat imgViewCenterY = 0;
CGFloat imgViewW = 80;
CGFloat imgViewH =imgViewW;
_radius = centerX - imgViewW * 0.5f;//imgView.center到self.center的距离
for (int i = 0; i < 6; i++) {
    currentAngle = _deltaAngle * i;
    imgViewCenterX = centerX + _radius * sin(currentAngle);
    imgViewCenterY = centerY - _radius * cos(currentAngle);
    UIImageView *imgView = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0, imgViewW, imgViewH)];
    imgView.tag = kTag + i;
    imgView.center = CGPointMake(imgViewCenterX, imgViewCenterY);
    imgView.image = [UIImage imageNamed:[NSString stringWithFormat:@"circle%d", i]];
    [self addSubview:imgView];
}

}

</br>
###2、转起来
</p>
######1)计算任意点相对于原点(O)及x轴的夹角⍺
</p>
![A点相对于原点及x轴角度][02]

> 以点A为例:
> ![][03]
> `CGFloat currentPointRadius = sqrt(pow(currentPoint.y - _centerPoint.y, 2) + pow(currentPoint.x - _centerPoint.x, 2));`
>
> ![][04]
> 所以,⍺ = arccos((A.x - O.x) / OA),`CGFloat curentPointAngle = acos((currentPoint.x - _centerPoint.x) / currentPointRadius);` **!!!注意,此处有坑**






</p>
> **坑在哪?**cos(x)和sin(x)的周期是2π,所以必定在求arccos(x)时一个值对应两个角度,此时需要判断点是在哪个象限(`对于cos函数来说,要判断点在第一、二象限还是在第三、四象限,如果是sin函数,则应该判断点是第二、三象限还是在第一、四象限`)再进行计算。
>
> *下面是以cos函数分析:*
> 如图003,点C和点D,C在第第二象限,D在第三象限,它们对应的值相同但对应的角度不同。
> 如果是C点,则`CGFloat curentPointAngle = acos((currentPoint.x - _centerPoint.x) / currentPointRadius);`
> 如果是D点,则`curentPointAngle = (π - curentPointAngle) + π = 2 * π - curentPointAngle;`
![003][003]

</p>

> **另外一个坑!!!**
> #####不要尝试用tan函数计算点相对于原点及x轴的夹角!
> ###不要尝试用tan函数计算点相对于原点及x轴的夹角!!
> #不要尝试用tan函数计算点相对于原点及x轴的夹角!!!
></p>
> *因为tan函数在`[0,2π]`区间有2个周期,用的话会有出现各种bug!*

######2)计算变化的角度 𝝙
</p>
以1)方法计算当前点的角度`curentPointAngle` 
上一个点的角度`lastAngle`
则变化角度`CGFloat angle = lastAngle - curentPointAngle;` 
######3)改变6个imgView中心点位置
</p>
_lastImgViewAngle = fmod(_lastImgViewAngle + angle, 2 * M_PI);//对当前角度取模
CGFloat currentAngle = 0;
CGFloat imgViewCenterX = 0;
CGFloat imgViewCenterY = 0;
for (int i = 0; i < 6; i++) {
    UIImageView *imgView = [self viewWithTag:kTag];
    currentAngle = _deltaAngle * i + _lastImgViewAngle;
    imgViewCenterX = _centerPoint.x + _radius * sin(currentAngle);
    imgViewCenterY = _centerPoint.x - _radius * cos(currentAngle);
    imgView = [self viewWithTag:kTag + i];
    imgView.center = CGPointMake(imgViewCenterX, imgViewCenterY);
}
</p>
######4)旋转逻辑代码
</p>
  • (void)touchesBegan:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event {

    UITouch *touch = [touches anyObject]; CGPoint point = [touch locationInView:self]; //计算上一个点相对于x轴的角度 CGFloat lastPointRadius = sqrt(pow(point.y - _centerPoint.y, 2) + pow(point.x - _centerPoint.x, 2)); if (lastPointRadius == 0) { return; } _lastPointAngle = acos((point.x - _centerPoint.x) / lastPointRadius); if (point.y > _centerPoint.y) { _lastPointAngle = 2 * M_PI - _lastPointAngle; } }

  • (void)touchesMoved:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event {

    UITouch *touch = [touches anyObject]; CGPoint currentPoint = [touch locationInView:self];

    //1.计算当前点相对于x轴的角度 CGFloat currentPointRadius = sqrt(pow(currentPoint.y - _centerPoint.y, 2) + pow(currentPoint.x - _centerPoint.x, 2)); if (currentPointRadius == 0) {//当点在中心点时,被除数不能为0 return; } CGFloat curentPointAngle = acos((currentPoint.x - _centerPoint.x) / currentPointRadius); if (currentPoint.y > _centerPoint.y) { curentPointAngle = 2 * M_PI - curentPointAngle; } //2.变化的角度 CGFloat angle = _lastPointAngle - curentPointAngle;

    _blueView.transform = CGAffineTransformRotate(_blueView.transform, angle);

    _lastImgViewAngle = fmod(_lastImgViewAngle + angle, 2 * M_PI);//对当前角度取模 CGFloat currentAngle = 0; CGFloat imgViewCenterX = 0; CGFloat imgViewCenterY = 0; for (int i = 0; i < 6; i++) { UIImageView *imgView = [self viewWithTag:kTag]; currentAngle = _deltaAngle * i + _lastImgViewAngle; imgViewCenterX = _centerPoint.x + _radius * sin(currentAngle); imgViewCenterY = _centerPoint.x - _radius * cos(currentAngle); imgView = [self viewWithTag:kTag + i]; imgView.center = CGPointMake(imgViewCenterX, imgViewCenterY); }

    _lastPointAngle = curentPointAngle; }

</br>


- - -
最后,推荐一个同事[@shelin](http://www.jianshu.com/users/edad244257e2)分享的实用小工具,[iOS-Images-Extractor](https://github.com/devcxm/iOS-Images-Extractor.git),能快速获得iOS *.ipa包中的图片(包括Assets.car)。


[效果图]:http://upload-images.jianshu.io/upload_images/610137-84fa53199d8f99c3.gif?imageMogr2/auto-orient/strip
[center.001.jpg]:http://upload-images.jianshu.io/upload_images/610137-f186dc8d8acb7866.jpeg?imageMogr2/auto-orient/strip%7CimageView2/2/w/1240
[02]:http://upload-images.jianshu.io/upload_images/610137-97ec4578141eeda6.jpeg?imageMogr2/auto-orient/strip%7CimageView2/2/w/1240
[003]:http://upload-images.jianshu.io/upload_images/610137-53769d135250f5f0.jpeg?imageMogr2/auto-orient/strip%7CimageView2/2/w/1240
[03]:http://upload-images.jianshu.io/upload_images/610137-c9636b5bc43a20f7.latex?imageMogr2/auto-orient/strip
[04]:http://upload-images.jianshu.io/upload_images/610137-8710ff9591d56e3c.latex?imageMogr2/auto-orient/strip
[Demo]:https://github.com/JoanLeeo/CircleAnimation.git
[三角函数]:http://baike.baidu.com/link?url=GdonGbaM0lkRY8bZ4cm8JAcaU4AYZzqrCC9F6_EaqE2OiI63YOEy8fxvohTS22cP6_v2Eb9y8aYTExj38iTt2_

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