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implement-magic-dictionary.py
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implement-magic-dictionary.py
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# V0
# V1
# http://bookshadow.com/weblog/2017/09/10/leetcode-implement-magic-dictionary/
import collections
class MagicDictionary(object):
def __init__(self):
"""
Initialize your data structure here.
"""
self.dmap = collections.defaultdict(set)
def buildDict(self, dict):
"""
Build a dictionary through a list of words
:type dict: List[str]
:rtype: void
"""
for word in dict:
for x in range(len(word)):
key = word[:x] + '_' + word[x+1:]
self.dmap[key].add(word[x])
def search(self, word):
"""
Returns if there is any word in the trie that equals to the given word after modifying exactly one character
:type word: str
:rtype: bool
"""
for x in range(len(word)):
key = word[:x] + '_' + word[x+1:]
values = self.dmap[key]
if not values: continue
if word[x] not in values or len(values) > 1:
return True
return False
# Your MagicDictionary object will be instantiated and called as such:
# obj = MagicDictionary()
# obj.buildDict(dict)
# param_2 = obj.search(word)
# V2
# Time: O(n), n is the length of the word
# Space: O(d)
import collections
class MagicDictionary(object):
def __init__(self):
"""
Initialize your data structure here.
"""
_trie = lambda: collections.defaultdict(_trie)
self.trie = _trie()
def buildDict(self, dictionary):
"""
Build a dictionary through a list of words
:type dictionary: List[str]
:rtype: void
"""
for word in dictionary:
reduce(dict.__getitem__, word, self.trie).setdefault("_end")
def search(self, word):
"""
Returns if there is any word in the trie that equals to the given word after modifying exactly one character
:type word: str
:rtype: bool
"""
def find(word, curr, i, mistakeAllowed):
if i == len(word):
return "_end" in curr and not mistakeAllowed
if word[i] not in curr:
return any(find(word, curr[c], i+1, False) for c in curr if c != "_end") \
if mistakeAllowed else False
if mistakeAllowed:
return find(word, curr[word[i]], i+1, True) or \
any(find(word, curr[c], i+1, False) \
for c in curr if c not in ("_end", word[i]))
return find(word, curr[word[i]], i+1, False)
return find(word, self.trie, 0, True)