exchange_seats.sql

/*

626. Exchange Seats
Medium

SQL Schema
Mary is a teacher in a middle school and she has a table seat storing students' names and their corresponding seat ids.

The column id is continuous increment.

Mary wants to change seats for the adjacent students.

Can you write a SQL query to output the result for Mary?

 

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Abbot   |
|    2    | Doris   |
|    3    | Emerson |
|    4    | Green   |
|    5    | Jeames  |
+---------+---------+
For the sample input, the output is:

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Doris   |
|    2    | Abbot   |
|    3    | Green   |
|    4    | Emerson |
|    5    | Jeames  |
+---------+---------+
Note:

If the number of students is odd, there is no need to change the last one's seat.

*/

# V0

# V1
# https://leetcode.com/problems/exchange-seats/solution/
SELECT
    (CASE
        WHEN MOD(id, 2) != 0 AND counts != id THEN id + 1
        WHEN MOD(id, 2) != 0 AND counts = id THEN id
        ELSE id - 1
    END) AS id,
    student
FROM
    seat,
    (SELECT
        COUNT(*) AS counts
    FROM
        seat) AS seat_counts
ORDER BY id ASC;

# V1'
# https://leetcode.com/problems/exchange-seats/solution/
SELECT
    s1.id, COALESCE(s2.student, s1.student) AS student
FROM
    seat s1
        LEFT JOIN
    seat s2 ON ((s1.id + 1) ^ 1) - 1 = s2.id
ORDER BY s1.id;

# V1'
# https://ask.hellobi.com/blog/kiozc/33912
SELECT (CASE
            WHEN id % 2 = 1 AND id != C THEN id+1
            WHEN id % 2 = 1 AND id  = C THEN id
       ELSE id-1 END) AS id,student
FROM seat,(SELECT COUNT(1) AS C FROM seat) AS T
ORDER BY id;

# V2