[1040 Longest Symmetric String] may be

[absop]

#include <stdio.h>

int main()
{
    int longest = 1;
    char line[1024] = {0};
    gets(line + 1); /* line[0] as sentinel */

    char *lo, *hi;
    for (char *p = line + 1; *p; ++p) {
        for (lo = p; *lo == *p; --lo);
        for (hi = p; *hi == *p; ++hi);
        for (; *lo == *hi && *lo && *hi; --lo, ++hi);
        if (hi - lo - 1 > longest) longest = hi - lo - 1;
    }
    printf("%d\n", longest);

    return 0;
}

[tiny656]

#include <stdio.h>

int main()
{
    int longest = 1;
    char line[1024] = {0};
    gets(line + 1); /* line[0] as sentinel */

    char *lo, *hi;
    for (char *p = line + 1; *p; ++p) {
        for (lo = p; *lo == *p; --lo);
        for (hi = p; *hi == *p; ++hi);
        for (; *lo == *hi && *lo && *hi; --lo, ++hi);
        if (hi - lo - 1 > longest) longest = hi - lo - 1;
    }
    printf("%d\n", longest);

    return 0;
}

代码很简洁。😀

[absop]

谢谢，这是我的PAT的解答[PAT](https://github.com/absop/PAT)，可以瞧瞧😄 2913049342 邮箱：[email protected] 签名由 网易邮箱大师 定制 On 09/13/2019 09:35, Xin Li wrote: #include <stdio.h> int main() { int longest = 1; char line[1024] = {0}; gets(line + 1); /* line[0] as sentinel */ char *lo, *hi; for (char *p = line + 1; *p; ++p) { for (lo = p; *lo == *p; --lo); for (hi = p; *hi == *p; ++hi); for (; *lo == *hi && *lo && *hi; --lo, ++hi); if (hi - lo - 1 > longest) longest = hi - lo - 1; } printf("%d\n", longest); return 0; } 代码很简洁。😀 — You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub, or mute the thread.