- Class
- Instance variable
- Method
- Object
Object
- Set
- EventListner
- Collection
- Comparator
Collection
- Set
- List
- Comparator
- Collection
List
- Set
- List
- Array
- Collection
Set
A. double num1, int num2 = 0;
B. int num1, num2;
C. int num1, num2 = 0;
D. int num1 = 0, num2 = 0;
A. double num1, int num2 = 0;
public class Test {
public static void main(String[] args) {
for(int i = 0; i < 5; i++) {
System.out.println(i + ' ');
}
}
}
Output
32
33
34
35
36
import java.util.ArrayList;
public class Test {
public static void main(String[] args) {
ArrayList arrList = new ArrayList();
arrList.add(1);
arrList.add('1');
arrList.add("1");
System.out.println(arrList);
}
}
Output
[1, 1, 1]
public class Test {
public static void main(String[] args) {
for(int i=0; 0; i++) {
System.out.println("Hello World!");
}
}
}
Output
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
Type mismatch: cannot convert from int to boolean
at Test.main(Test.java:5)
A. It can only contain one class declaration.
B. It can contain one pulic class declaration and one public interface definition.
C. It must define at least one public class.
D. It may define at most one public class.
Answer: D
public class Test {
private static int one = 10;
int two = 20;
public static void main(String []args) {
Test test = new Test();
int today = 20; two = 40;
System.out.println(today + test.two + test.one);
}
}
Output
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
Cannot make a static reference to the non-static field two
at Test.main(Test.java:9)
public class Test{
static int start = 2;
final int end;
public Test(int x) {
x = 4;
end = x;
}
public void fly(int distance) {
System.out.println(end-start+" ");
System.out.println(distance);
}
public static void main(String []args){
new Test(10).fly(5);
}
}
Output
[2 5]
public class Test
{
public static void main(String a[]) {
try {
int val = 10/0;
} catch(Exception e) {
System.out.println(e);
} catch(ArithmeticException ae) {
System.out.println(ae);
}
}
}
Output
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
Unreachable catch block for ArithmeticException. It is already handled by the catch block for Exception
at Test.main(Test.java:12)
public class Test
{
static void charNum(String inputString) {
HashMap<Character, Integer> charMap = new HashMap<Character, Integer>();
char[] strArray = inputString.toCharArray();
for(char c: strArray) {
if(charMap.containsKey(c)) {
charMap.put(c, charMap.get(c)+1);
} else {
charMap.put(c, 1);
}
}
Set<Character> charInString = charMap.keySet();
for(Character ch: charInString) {
if(charMap.get(ch) > 1) {
System.out.println(ch +" : "+ charMap.get(ch));
}
}
}
public static void main(String[] args) {
charNum("JavaJ2Ee");
}
}
Output
a : 2
J : 2
A. double num1, int num2 = 0;
B. int num1, num2;
C. int num1, num2 = 0;
D. int num1 = 0, num2 = 0;
A. double num1, int num2 = 0;
Explanation: A. Option A does not compile because Java does not allow declaring different types as part of the same declaration.
public static void main(String... args) {
String chair, table = "metal";
chair = chair + table;
System.out.println(chair);
}
A. metal
B. metalmetal
C. nullmetal
D. The code does not compile
D. The code does not compile
Explanation: The local variable chair may not have been initialized
A. It defaults to an empty string.
B. It defaults to null.
C. It does not have a default value.
D. It will not compile without initializing on the declaration line
B. It defaults to null.
public class Test
{
public String convert(int value) {
return value.toString();
}
public String convert(Integer value) {
return value.toString();
}
public String convert(Object value) {
return value.toString();
}
public static void main(String... args) {
Test obj = new Test();
System.out.println(obj.convert(10));
}
}
A. None
B. One
C. Two
D. Three
C. Two
Explanation: Objects have instance methods while primitives do not. Since int is a primitive, you cannot call instance methods on it. Integer and String are both objects and have instance methods.
A. int num = 999;
B. int num = 9_9_9;
C. int num = _9_99;
D. None of the above; they all compile.
C. int num = _9_99;
double d1 = 5f; // p1
double d2 = 5.0; // p2
float f1 = 5f; // p3
float f2 = 5.0; // p4
A. p1
B. p2
C. p3
D. p4
D. P4
Explanation: Type mismatch: cannot convert from double to float
public class Bowling {
{
System.out.println();
}
public Bowling () {
System.out.println();
}
static {
System.out.println();
}
{
System.out.println();
}
}
A. None
B. One
C. Two
D. Three
C. Two
A. It may be called zero or one times.
B. It may be called zero or more times.
C. It will be called exactly once.
D. It may be called one or more times.
A. It may be called zero or one times.
Explanation: The finalize()
method may not be called, such as if your program crashes. However, it is guaranteed to be called no more than once.
A. You can call methods on a primitive.
B. You can convert a primitive to a wrapper class object simply by assigning it.
C. You can convert a wrapper class object to a primitive by calling valueOf().
D. You can store a primitive directly into an ArrayList.
B. You can convert a primitive to a wrapper class object simply by assigning it.
Integer integer = new Integer(4);
System.out.print(integer.byteValue());
System.out.print("-");
int i = new Integer(4);
System.out.print(i.byteValue());
A. 4-0
B. 4-4
C. The code does not compile.
D. The code compiles but throws an exception at runtime
C. The code does not compile.
Q. Which two primitives have wrapper classes that are not merely the name of the primitive with an uppercase letter?
A. byte and char
B. byte and int
C. char and int
D. None of the above
C. char and int
Explanation: The wrapper class for int is Integer and the wrapper class for char is Character. All other primitives have the same name. For example, the wrapper class for boolean is Boolean.
A. Call System.forceGc()
B. Call System.gc()
C. Call System.requireGc()
D. None of the above
D. None of the above
Explanation: While you can suggest to the JVM that it might want to run a garbage collection cycle, the JVM is free to ignore your suggestion.
Q. How many of the String objects are eligible for garbage collection right before the end of the main method?
public static void main(String[] fruits) {
String fruit1 = new String("apple");
String fruit2 = new String("orange");
String fruit3 = new String("pear");
fruit3 = fruit1;
fruit2 = fruit3;
fruit1 = fruit2;
}
A. None
B. One
C. Two
D. Three
C. Two
Explanation: All three references point to the String apple. This makes the other two String objects eligible for garbage collection.
A. double num = 2.718;
B. double num = 2._718;
C. double num = 2.7_1_8;
D. None of the above; they all compile
B. double num = 2._718;
Explanation: Underscores are allowed between any two digits in a numeric literal. Underscores are not allowed adjacent to a decimal point
public class Toy {
public void play() {
System.out.print("play-");
}
public void finalizer() {
System.out.print("clean-");
}
public static void main(String[] fun) {
Toy car = new Toy();
car.play();
System.gc();
Toy doll = new Toy();
doll.play();
}
}
A. play-
B. play-play-
C. play-clean-play-
D. play-play-clean-clean-
B. play-play-
Explanation: If there was a finalize() method, this would be a different story. However, the method here is finalizer. Tricky! That’s just a normal method that doesn’t get called automatically. Therefore clean is never output.
int meal = 5;
int tip = 2;
int total = meal + (meal>6 ? ++tip : --tip);
A. 1
B. 2
C. 3
D. 6
D. 6
Explanation: In ternary expressions, only one of the two right-most expressions are evaluated. Since meal>6
is false, ––tip
is evaluated and ++tip
is skipped. tip
is changed from 2 to 1 and total
becomes meal + (1)
which means 5 + 1 = 6
.
String john = "john";
String jon = new String(john);
System.out.println((john==jon) + " "+ (john.equals(jon)));
A. true true
B. true false
C. false true
D. false false
C. false true