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How is the proposition in session 7 task 2 even valid? #139

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eeropomell opened this issue Jun 2, 2023 · 3 comments
Open

How is the proposition in session 7 task 2 even valid? #139

eeropomell opened this issue Jun 2, 2023 · 3 comments

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@eeropomell
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How is this proposition valid? The premise says that for all x, if r(x) is false then r(f(x)). So r(x) can clearly be false for all x. BUT the conclusion states that there exists an x such that r(x) is true??

@NicoleRauch
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So r(x) can clearly be false for all x.

No, it can’t, because if it is false for a given x, then the premise states that it must be true for f(x). So there must be at least one value for which r is true. Which is the first half of the conclusion 😊

@nomeata
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nomeata commented Jun 3, 2023

Good explanation! It's worth adding that in our logic, the universe is never empty, (exists x. True is an axiom, so to say), else the above would not be a theorem.

@NicoleRauch
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There is always something I am missing out on 😆

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