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minimum-operations-to-remove-adjacent-ones-in-matrix.py
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minimum-operations-to-remove-adjacent-ones-in-matrix.py
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# Time: O(E * sqrt(V)) = O(m * n * sqrt(m * n))
# Space: O(V) = O(m * n)
from functools import partial
# Time: O(E * sqrt(V))
# Space: O(V)
# Source code from http://code.activestate.com/recipes/123641-hopcroft-karp-bipartite-matching/
# Hopcroft-Karp bipartite max-cardinality matching and max independent set
# David Eppstein, UC Irvine, 27 Apr 2002
def bipartiteMatch(graph):
'''Find maximum cardinality matching of a bipartite graph (U,V,E).
The input format is a dictionary mapping members of U to a list
of their neighbors in V. The output is a triple (M,A,B) where M is a
dictionary mapping members of V to their matches in U, A is the part
of the maximum independent set in U, and B is the part of the MIS in V.
The same object may occur in both U and V, and is treated as two
distinct vertices if this happens.'''
# initialize greedy matching (redundant, but faster than full search)
matching = {}
for u in graph:
for v in graph[u]:
if v not in matching:
matching[v] = u
break
while 1:
# structure residual graph into layers
# pred[u] gives the neighbor in the previous layer for u in U
# preds[v] gives a list of neighbors in the previous layer for v in V
# unmatched gives a list of unmatched vertices in final layer of V,
# and is also used as a flag value for pred[u] when u is in the first layer
preds = {}
unmatched = []
pred = dict([(u,unmatched) for u in graph])
for v in matching:
del pred[matching[v]]
layer = list(pred)
# repeatedly extend layering structure by another pair of layers
while layer and not unmatched:
newLayer = {}
for u in layer:
for v in graph[u]:
if v not in preds:
newLayer.setdefault(v,[]).append(u)
layer = []
for v in newLayer:
preds[v] = newLayer[v]
if v in matching:
layer.append(matching[v])
pred[matching[v]] = v
else:
unmatched.append(v)
# did we finish layering without finding any alternating paths?
if not unmatched:
unlayered = {}
for u in graph:
for v in graph[u]:
if v not in preds:
unlayered[v] = None
return (matching,list(pred),list(unlayered))
# recursively search backward through layers to find alternating paths
# recursion returns true if found path, false otherwise
def recurse(v):
if v in preds:
L = preds[v]
del preds[v]
for u in L:
if u in pred:
pu = pred[u]
del pred[u]
if pu is unmatched or recurse(pu):
matching[v] = u
return 1
return 0
def recurse_iter(v):
def divide(v):
if v not in preds:
return
L = preds[v]
del preds[v]
for u in L :
if u in pred and pred[u] is unmatched: # early return
del pred[u]
matching[v] = u
ret[0] = True
return
stk.append(partial(conquer, v, iter(L)))
def conquer(v, it):
for u in it:
if u not in pred:
continue
pu = pred[u]
del pred[u]
stk.append(partial(postprocess, v, u, it))
stk.append(partial(divide, pu))
return
def postprocess(v, u, it):
if not ret[0]:
stk.append(partial(conquer, v, it))
return
matching[v] = u
ret, stk = [False], []
stk.append(partial(divide, v))
while stk:
stk.pop()()
return ret[0]
for v in unmatched: recurse_iter(v)
import collections
class Solution(object):
def minimumOperations(self, grid):
"""
:type grid: List[List[int]]
:rtype: int
"""
directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]
def iter_dfs(grid, i, j, lookup, adj):
if lookup[i][j]:
return
lookup[i][j] = True
stk = [(i, j, (i+j)%2)]
while stk:
i, j, color = stk.pop()
for di, dj in directions:
ni, nj = i+di, j+dj
if not (0 <= ni < len(grid) and 0 <= nj < len(grid[0]) and grid[ni][nj]):
continue
if not color:
adj[len(grid[0])*ni+nj].append(len(grid[0])*i+j)
if lookup[ni][nj]:
continue
lookup[ni][nj] = True
stk.append((ni, nj, color^1))
adj = collections.defaultdict(list)
lookup = [[False]*len(grid[0]) for _ in xrange(len(grid))]
for i in xrange(len(grid)):
for j in xrange(len(grid[0])):
if not grid[i][j]:
continue
iter_dfs(grid, i, j, lookup, adj)
return len(bipartiteMatch(adj)[0])