forked from kamyu104/LeetCode-Solutions
-
Notifications
You must be signed in to change notification settings - Fork 0
/
continuous-subarrays.py
91 lines (80 loc) · 2.49 KB
/
continuous-subarrays.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
# Time: O(n)
# Space: O(1)
import collections
# two pointers
class Solution(object):
def continuousSubarrays(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = left = 0
mn, mx = float("inf"), float("-inf")
for right in xrange(len(nums)):
if mn <= nums[right] <= mx:
mn, mx = max(mn, nums[right]-2), min(mx, nums[right]+2)
else:
mn, mx = nums[right]-2, nums[right]+2
for left in reversed(xrange(right)):
if not mn <= nums[left] <= mx:
break
mn, mx = max(mn, nums[left]-2), min(mx, nums[left]+2)
else:
left = -1
left += 1
result += right-left+1
return result
# Time: O(n)
# Space: O(n)
import collections
# mono deque, two pointers
class Solution2(object):
def continuousSubarrays(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
mn, mx = collections.deque(), collections.deque()
result = left = 0
for right in xrange(len(nums)):
while mn and nums[mn[-1]] > nums[right]:
mn.pop()
mn.append(right)
while mx and nums[mx[-1]] < nums[right]:
mx.pop()
mx.append(right)
while not nums[right]-nums[mn[0]] <= 2:
left = max(left, mn.popleft()+1)
while not nums[mx[0]]-nums[right] <= 2:
left = max(left, mx.popleft()+1)
result += right-left+1
return result
# Time: O(nlogn)
# Space: O(n)
from sortedcontainers import SortedDict
# ordered dict, two pointers
class Solution3(object):
def continuousSubarrays(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = left = 0;
lookup = SortedDict()
for right in xrange(len(nums)):
lookup[nums[right]] = right
to_del = []
for x, i in lookup.items():
if nums[right]-x <= 2:
break
left = max(left, i+1)
to_del.append(x)
for x, i in reversed(lookup.items()):
if x-nums[right] <= 2:
break
left = max(left, i+1)
to_del.append(x)
for x in to_del:
del lookup[x]
result += right-left+1;
return result;