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0107-binary-tree-level-order-traversal-ii.adoc

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107. Binary Tree Level Order Traversal II

{leetcode}/problems/binary-tree-level-order-traversal-ii/[LeetCode - Binary Tree Level Order Traversal II^]

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).

For example:
Given binary tree [3,9,20,null,null,15,7],

   3
  / \
 9  20
   /  \
  15   7

return its bottom-up level order traversal as:

[
  [15,7],
  [9,20],
  [3]
]

解题分析

分层访问,然后再把顺序反转过来。

思考题

尝试一下递归的解法!

参考资料

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).

For example:

Given binary tree [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7

return its bottom-up level order traversal as:

[
  [15,7],
  [9,20],
  [3]
]
link:{sourcedir}/_0107_BinaryTreeLevelOrderTraversalII.java[role=include]
link:{sourcedir}/_0107_BinaryTreeLevelOrderTraversalII_2.java[role=include]

相比第一次解,第二次解直接在链表前面添加元素即可,这样就无需反转了。