Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has the largest sum = 6.
More practice: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
Kadane's演算法能夠使用一個迴圈得出答案,若要更快速就要使用分而治之來實作了,間單來說Kadane's演算法就是當遇到負數就歸零,每次相加結果取最大數。
- 陣列走訪
- Run Time: 6 ms
- 時間複雜度: O(n)
- 空間複雜度: O(1)
int maxSubArray(int * nums, int numsSize) {
int i = 0, tot = 0, max = INT_MIN;
for (; i < numsSize; i++) {
tot += nums[i];
if (max < tot)
max = tot;
if (tot < 0)
tot = 0;
}
return max;
}