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sort.py
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sort.py
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# coding: utf-8
"""
FROM: <https://github.com/vinta/awesome-python/blob/master/sort.py>
The approach taken is explained below. I decided to do it simply.
Initially I was considering parsing the data into some sort of
structure and then generating an appropriate README. I am still
considering doing it - but for now this should work. The only issue
I see is that it only sorts the entries at the lowest level, and that
the order of the top-level contents do not match the order of the actual
entries.
This could be extended by having nested blocks, sorting them recursively
and flattening the end structure into a list of lines. Revision 2 maybe ^.^.
"""
def main():
# First, we load the current README into memory as an array of lines
with open('README.md', 'r') as read_me_file:
read_me = read_me_file.readlines()
# Then we cluster the lines together as blocks
# Each block represents a collection of lines that should be sorted
# This was done by assuming only links ([...](...)) are meant to be sorted
# Clustering is done by indentation
blocks = []
last_indent = None
for line in read_me:
s_line = line.lstrip()
indent = len(line) - len(s_line)
if any([s_line.startswith(s) for s in ['* [', '- [']]):
if indent == last_indent:
blocks[-1].append(line)
else:
blocks.append([line])
last_indent = indent
else:
blocks.append([line])
last_indent = None
with open('README.md', 'w+') as sorted_file:
# Then all of the blocks are sorted individually
blocks = [''.join(sorted(block, key=lambda s: s.lower())) for block in blocks]
# And the result is written back to README.md
sorted_file.write(''.join(blocks))
if __name__ == "__main__":
main()