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rgbhex.go
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rgbhex.go
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// rgbhex.go
// description: convert hex input to red, green and blue and vice versa
// time complexity: O(1)
// space complexity: O(1)
// author(s) [darmiel](https://github.com/darmiel)
// see rgbhex_test.go
package conversion
// HEXToRGB splits an RGB input (e.g. a color in hex format; 0x<color-code>)
// into the individual components: red, green and blue
func HEXToRGB(hex uint) (red, green, blue byte) {
// A hex code is structured like this:
// #3498db (light blue) - converted to binary:
// 00110100 10011000 11011011
// <red> <green> <blue>
// To get the blue value we use the bit operation AND with the bit mask 0xFF (in binary: 11111111)
// 00110100 10011000 <11011011> &
// 00000000 00000000 11111111 =
// 00000000 00000000 <11011011> =
blue = byte(hex & 0xFF)
// To get the green value, we first shift the value 8 bits to the right:
// 00110100 <10011000> 11011011 >> 8 =
// 00000000 00110100 <10011000> &
// 00000000 00000000 11111111 =
// 00000000 00000000 <10011000> =
green = byte((hex >> 8) & 0xFF)
// Same as green value, only this time shift 16 to the right
// Alternatively, you can apply a bitmask first and then shift it.
// <00110100> 10011000 11011011 &
// 11111111 00000000 00000000 =
// <00110100> 00000000 00000000 >> 16
// 00000000 00000000 <00110100> =
red = byte((hex >> 16) & 0xFF)
return
}
// RGBToHEX does exactly the opposite of HEXToRGB:
// it combines the three components red, green and blue to an RGB value, which can be converted to e.g. Hex
func RGBToHEX(red, green, blue byte) (hex uint) {
// Sets the bits of blue in position 1-8, green in 9-16 and red in 17-24
// Red: 00110100
// Green: 10011000
// Blue: 11011011
// RGB:
// R << 16: [00110100] 00000000 00000000 |
// G << 8 : 00000000 {10011000} 00000000 |
// B : 00000000 00000000 <11011011> =
// [00110100] {10011000} <11011011>
return (uint(red) << 16) | (uint(green) << 8) | uint(blue)
}