[🐛 Bug]: raise WebDriverException( selenium.common.exceptions.WebDriverException)

[skybird2022]

What happened?

Hi Support Team,

After I upgraded selenium version from 4.6.0 to 4.22.0 in Pycharm, it encountered following errors ( Please refer to attached screen captures with bugs) . I checked my local environment variable setting is no problem, and chromedriver version match with Google Chrome. I also open selenium-manager.exe, there is a error too. Can you help to check the root cause of these errors ? Thanks for support !

In order not to affect my daily work, I uninstall 4.22.0, and re-install temporarily 4.6.0 for workaround.

How can we reproduce the issue?

for example: 

from selenium import webdriver
driver = webdriver.Chrome()
driver.get('https://www.baidu.com/')

Relevant log output

Traceback (most recent call last):
  File "G:\Python\lib\site-packages\selenium\webdriver\common\driver_finder.py", line 67, in _binary_paths
    output = SeleniumManager().binary_paths(self._to_args())
  File "G:\Python\lib\site-packages\selenium\webdriver\common\selenium_manager.py", line 53, in binary_paths
    return self._run(args)
  File "G:\Python\lib\site-packages\selenium\webdriver\common\selenium_manager.py", line 118, in _run
    raise WebDriverException(
selenium.common.exceptions.WebDriverException: Message: Unsuccessful command executed: G:\Python\lib\site-packages\selenium\webdriver\common\windows\selenium-manager.exe --browser chrome --language-binding python --output json; code: 3221225477
{}

The above exception was the direct cause of the following exception:


Traceback (most recent call last):
  File "F:/Pycharm/Projects/aaa.py", line 8, in <module>
    driver = webdriver.Chrome()
  File "G:\Python\lib\site-packages\selenium\webdriver\chrome\webdriver.py", line 45, in __init__
    super().__init__(
  File "G:\Python\lib\site-packages\selenium\webdriver\chromium\webdriver.py", line 50, in __init__
    if finder.get_browser_path():
  File "G:\Python\lib\site-packages\selenium\webdriver\common\driver_finder.py", line 47, in get_browser_path
    return self._binary_paths()["browser_path"]
  File "G:\Python\lib\site-packages\selenium\webdriver\common\driver_finder.py", line 78, in _binary_paths
    raise NoSuchDriverException(msg) from err
selenium.common.exceptions.NoSuchDriverException: Message: Unable to obtain driver for chrome; For documentation on this error, please visit: https://www.selenium.dev/documentation/webdriver/troubleshooting/errors/driver_location

Operating System

Window 7

Selenium version

4.22.0

What are the browser(s) and version(s) where you see this issue?

Chrome - 109.0.5414.120

What are the browser driver(s) and version(s) where you see this issue?

ChromeDriver - 109.0.5414.25

Are you using Selenium Grid?

No

[github-actions]

@skybird2022, thank you for creating this issue. We will troubleshoot it as soon as we can.

---

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Thank you!

[github-actions]

We need more information about this issue in order to troubleshoot.

Please turn on logging and re-run your code. Information on how to adjust logs for your language can be found in our
Troubleshooting documentation.

[skybird2022]

We need more information about this issue in order to troubleshoot.

Please turn on logging and re-run your code. Information on how to adjust logs for your language can be found in our Troubleshooting documentation.

Hi Support Team, please refer to above "Relevant log output" details.

[diemol]

Check the link; it has instructions on how to enable debug logging.

Troubleshooting documentation.

[skybird2022]

Check the link; it has instructions on how to enable debug logging.

Troubleshooting documentation.

Hi Diemol, I try to logging it according to your advise, it's not workable. I have find out the solution from official document. For higher version(4.6.0 or above ), I tested by using Service object to dedicate the path of chromedriver, it's workable. Therefore, seems there is no relationship between high-version and setting-driven environment variables.

Anyway, thanks for your support and prompt reply.

[diemol]

Thanks for letting us know.