203.md

Reverse Linked List

Description

link

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Solution

See Code

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Code

O(n)

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def reverseList(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        pre = None
        while head:
            cur = head
            head = head.next
            cur.next = pre
            pre = cur
        return pre