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JSONCrush.js
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JSONCrush.js
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/////////////////////////////////////////////////////////////////////////////////
// JSONCrush v1.1.6 by Frank Force - https://github.com/KilledByAPixel/JSONCrush
/////////////////////////////////////////////////////////////////////////////////
'use strict';
export default
{
crush: (string, maxSubstringLength=50)=>
{
const delimiter = '\u0001'; // used to split parts of crushed string
const JSCrush=(string, replaceCharacters)=>
{
// JSCrush Algorithm (repleace repeated substrings with single characters)
let replaceCharacterPos = replaceCharacters.length;
let splitString = '';
const ByteLength =(string)=>encodeURI(encodeURIComponent(string)).replace(/%../g,'i').length;
const HasUnmatchedSurrogate =(string)=>
{
// check ends of string for unmatched surrogate pairs
let c1 = string.charCodeAt(0);
let c2 = string.charCodeAt(string.length-1);
return (c1 >= 0xDC00 && c1 <= 0xDFFF) || (c2 >= 0xD800 && c2 <= 0xDBFF);
}
// count instances of substrings
let substringCount = {};
for (let substringLength = 2; substringLength < maxSubstringLength; substringLength++)
for (let i = 0; i < string.length - substringLength; ++i)
{
let substring = string.substr(i, substringLength);
// don't recount if already in list
if (substringCount[substring])
continue;
// prevent breaking up unmatched surrogates
if (HasUnmatchedSurrogate(substring))
continue;
// count how many times the substring appears
let count = 1;
for (let substringPos = string.indexOf(substring, i+substringLength); substringPos >= 0; ++count)
substringPos = string.indexOf(substring, substringPos + substringLength);
// add to list if it appears multiple times
if (count > 1)
substringCount[substring] = count;
}
while(true) // loop while string can be crushed more
{
// get the next character that is not in the string
for (;replaceCharacterPos-- && string.includes(replaceCharacters[replaceCharacterPos]);){}
if (replaceCharacterPos < 0)
break; // ran out of replacement characters
let replaceCharacter = replaceCharacters[replaceCharacterPos];
// find the longest substring to replace
let bestSubstring;
let bestLengthDelta = 0;
let replaceByteLength = ByteLength(replaceCharacter);
for (let substring in substringCount)
{
// calculate change in length of string if it substring was replaced
let count = substringCount[substring];
let lengthDelta = (count-1)*ByteLength(substring) - (count+1)*replaceByteLength;
if (!splitString.length)
lengthDelta -= ByteLength(delimiter); // include the delimiter length
if (lengthDelta <= 0)
delete substringCount[substring]
else if (lengthDelta > bestLengthDelta)
{
bestSubstring = substring
bestLengthDelta = lengthDelta;
}
}
if (!bestSubstring)
break; // string can't be compressed further
// create new string with the split character
string = string.split(bestSubstring).join(replaceCharacter) + replaceCharacter + bestSubstring;
splitString = replaceCharacter + splitString;
// update substring count list after the replacement
let newSubstringCount = {};
for (let substring in substringCount)
{
// make a new substring with the replacement
let newSubstring = substring.split(bestSubstring).join(replaceCharacter);
// count how many times the new substring appears
let count = 0;
for (let i = string.indexOf(newSubstring); i >= 0; ++count)
i = string.indexOf(newSubstring, i + newSubstring.length);
// add to list if it appears multiple times
if (count > 1)
newSubstringCount[newSubstring] = count;
}
substringCount = newSubstringCount;
}
return {a:string, b:splitString};
}
// create a string of replacement characters
let characters = [];
// prefer replacing with characters that will not be escaped by encodeURIComponent
const unescapedCharacters = `-_.!~*'()`;
for (let i=127; --i;)
{
if
(
(i>=48 && i<=57) || // 0-9
(i>=65 && i<=90) || // A-Z
(i>=97 && i<=122)|| // a-z
unescapedCharacters.includes(String.fromCharCode(i))
)
characters.push(String.fromCharCode(i));
}
// pick from extended set last
for (let i=32; i<255; ++i)
{
let c = String.fromCharCode(i);
if (c!='\\' && !characters.includes(c))
characters.unshift(c);
}
// remove delimiter if it is found in the string
string = string.replace(new RegExp(delimiter,'g'),'');
// swap out common json characters
string = JSONCrushSwap(string);
// crush with JS crush
const crushed = JSCrush(string, characters);
// insert delimiter between JSCrush parts
let crushedString = crushed.a;
if (crushed.b.length)
crushedString += delimiter + crushed.b;
// fix issues with some links not being recognized properly
crushedString += '_';
// return crushed string
return crushedString;
},
uncrush: (string)=>
{
// remove last character
string = string.substring(0, string.length - 1);
// unsplit the string using the delimiter
const stringParts = string.split('\u0001');
// JSUncrush algorithm
let uncrushedString = stringParts[0];
if (stringParts.length > 1)
{
let splitString = stringParts[1];
for (let character of splitString)
{
// split the string using the current splitCharacter
let splitArray = uncrushedString.split(character);
// rejoin the string with the last element from the split
uncrushedString = splitArray.join(splitArray.pop());
}
}
// unswap the json characters in reverse direction
return JSONCrushSwap(uncrushedString, 0);
}
} // JSONCrush
const JSONCrushSwap = (string, forward=1)=>
{
// swap out characters for lesser used ones that wont get escaped
const swapGroups =
[
['"', "'"],
["':", "!"],
[",'", "~"],
['}', ")", '\\', '\\'],
['{', "(", '\\', '\\'],
];
const swapInternal=(string, g)=>
{
let regex = new RegExp(`${(g[2]?g[2]:'')+g[0]}|${(g[3]?g[3]:'')+g[1]}`,'g');
return string.replace(regex, $1 => ($1 === g[0] ? g[1] : g[0]));
}
// need to be able to swap characters in reverse direction for uncrush
if (forward)
for (let i = 0; i < swapGroups.length; ++i)
string = swapInternal(string, swapGroups[i]);
else
for (let i = swapGroups.length; i--;)
string = swapInternal(string, swapGroups[i]);
return string;
}