You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
class Solution:
def climbStairs(self, n):
"""
:type n: int
:rtype: int
"""
if n==1:
return 1
lst = [0] * n
print(lst)
lst[0]=1
lst[1]=2
for i in range(2,n):
lst[i]=lst[i-1]+lst[i-2]
return lst[n-1]
说明:动态规划问题,第n步的情况=第n-1步+第n-2步
- 初始状态
- 状态转移方程