Skip to content

Latest commit

 

History

History
50 lines (40 loc) · 949 Bytes

70climbing stairs.md

File metadata and controls

50 lines (40 loc) · 949 Bytes

You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

Note: Given n will be a positive integer.

Example 1:

Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps

Example 2:

Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
class Solution:
    def climbStairs(self, n):
        """
        :type n: int
        :rtype: int
        """
        if n==1:
            return 1
        lst = [0] * n
        print(lst)
        lst[0]=1
        lst[1]=2
        for i in range(2,n):
            lst[i]=lst[i-1]+lst[i-2]
        return lst[n-1]

说明:动态规划问题,第n步的情况=第n-1步+第n-2步

  1. 初始状态
  2. 状态转移方程