solution0001.js

// Given an integer n, return a string array answer(1 - indexed) where:

// answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
// answer[i] == "Fizz" if i is divisible by 3.
// answer[i] == "Buzz" if i is divisible by 5.
// answer[i] == i(as a string) if none of the above conditions are true.


//     Example 1:

// Input: n = 3
// Output: ["1", "2", "Fizz"]
// Example 2:

// Input: n = 5
// Output: ["1", "2", "Fizz", "4", "Buzz"]
// Example 3:

// Input: n = 15
// Output: ["1", "2", "Fizz", "4", "Buzz", "Fizz", "7", "8", "Fizz", "Buzz", "11", "Fizz", "13", "14", "FizzBuzz"]


// Constraints:

// 1 <= n <= 104

/**
 * @param {number} n
 * @return {string[]}
 */

//if i is divisible by 3 and 5 return the result
//we are going to loop thru an array and then ask if the elements can be divided by 3 & 5, just 3 and just 5. 
function fizzBuzz(n) {
    let answer = []

    for (let i = 1; i <= n; i++) {
        if (i % 3 === 0 && i % 5 === 0) {
            answer.push("FizzBuzz")
        } else if (i % 3 === 0) {
            answer.push("Fizz")
        } else if (i % 5 === 0) {
            answer.push("Buzz")
        } else {
            answer.push(i.toString())
        }
    }
    return answer
};